(4^2x-4)/(2^x-2)=126

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Solution for (4^2x-4)/(2^x-2)=126 equation: 



(4^2x-4)/(2^x-2)=126

We move all terms to the left:

(4^2x-4)/(2^x-2)-(126)=0



Domain of the equation: (2^x-2)!=0

We move all terms containing x to the left, all other terms to the right

2^x!=2

x!=2/1

x!=2

x∈R



We multiply all the terms by the denominator


(4^2x-4)-126*(2^x-2)=0

We multiply parentheses

(4^2x-4)-252x+252=0

We get rid of parentheses

4^2x-252x-4+252=0

We add all the numbers together, and all the variables

-252x+4^2x+248=0

We move all terms containing x to the left, all other terms to the right

-252x+4^2x=-248

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